MAXIMA AND MINIMA OF DISTANT FUNCITONALITY inetrveining slope of intervals(new derivations)

if the slope of dy/dx not first derivative coordinates we ogt we got the itersetct point by the dy//dx = zero and intersetc point of x and y this proof for inetersect slope of first derivative with equaliyt of slope comarison with d2y/dxssure to drive the cocoridnate value eitehr x and eitehr y we do derivation of the means firts deriavaiton of fucniton y=2xcube-3xsquare+6 and then it value is coming x=0,1 thne dy/dx=0 second deriavite comes 6 thne d2y/dxsquqre=12x-6 thne x = 1/2 thne then (0,6) to put x=0 in y then 1 fucntion y then x= 1 then y =2-3+6=5 (1,5) then make then x,y cooradinate (0,1) and (1,5) then make distance betwene them same ways now secodn derviate value comes 6 then put the diatsnce bwteeme (0,1) an (1,5) in the 12x-6, 12x-6 we put teh distcne of between then sloper y1-y2/x1-x2 then thwn 12x-6 = y1-y2/x1-x2 is equal 12x-6 = 5-1/1-0 then by that we ellebs the x 12x-6 = 4/1 then 12x-6 = 4 12x = 10 x = 10/12 because if for and hy and x m is dy/dx is m then the dy/dx is m for d2y/dxsuqare here i codnei the d2y/dxsquare in general form slope with dy/dx means to find the maxima against the if the slope of dy/dx not first derivative coordinates we ogt we got the itersetct point this enw proof for inetersect slope of first derivative with equaliyt fos lope comarison with d2y/dxssure to drive the cocoridnate value eitehr x and eitehr y

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