COLLATZ CONJUCTURE NEGATION AND SOLUTION

in collatz conjucture where f(n) have n/2 if n=0 (mod 2) have 3n+1 if n=1(mod 2) so we have factorila of the number to sove this poroblem fucntion is factorisl f(fatcoria n) so the values that coems by n/2 is it conervt isn fatcorial n and same way 3n+1 also conevrt in the here if n=1(mod 2) if we take fatcorisl mean m) anothr soaiton f(fatctrorial n ,factorial m) have n/2 if factorial n=0 mod 2 have 3m+1 if fatorial m=1 mod2 f(factoril n and factroial m of any size numebr) have n/2 if factorial n=0(mod 2) have 3m+1 if fatcorial m=1 mod2 fucniton then m,n then For instance, starting with n = 12 and applying the function f without "shortcut", one gets the sequence 12, 6, 3, 10, 5, 16, 8, 4, 2, 1. anotehr solutio two soltion in difefrn ways if n =6 f(factorial n) have n/2 if factorial n=0(mod 2) have 3n+1 if factorial n=1(mod2) or f(n) have factr n/2 if n=0(mod 2) have fact 3n+1 if n=1(mod 2) - -

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