reimann zeta function solution BY AM HYPOTHESIS

my solution if all numbers comes from curvical states if we take roatation against the curvcial state like parabola ζ(s) = 1 + 1/2pows + 1/3pows + 1/4pwos + … now teh fucntion ζ(ysqure=4ax) = 1 + 1/2pow4ax1 + 1/3pow4ax2 + 1/4pow4ax3 + … and if we take cofficient of of thenw eput value of curves meanss ortation aordn curves then ζ(ysqure=4ax) = 1 + 1/2pow4ax1pow theat + 1/3pow4ax2pow theat + 1/4pow4ax3 pow theat+ … then reiamns hyphstheis will return the a values that is not close to zero so its multilevel roaiton of numbers when it happens then if zete funciton will be complex hne it complex whne it become complex whne curve on angle theta will levae th state of the real part then complex state come s arised when it elave it beocmes the for ellispse and hyperbola same way my fucntion gives differ reuslts on curves even for 1+x+xsquqre as curve it differs the law of hypothesis so if 2powyax1powtheta1 is not equal to 2pows or equak to just by sisngel rotation my zeta fucntion givngn ration to numebr so 2pow4ax1pow theta = any number n then 2pow4ax1 = npow-theta then we take like that so we achives more thne that ist algorihtm if the numbe rins no trivals ad reimamn hypthesisc coomes then convert it in any blushc hole of ten curve just like valiues thenw eocudl achives th rpation of if ration fo the number in curve then angaulr then ther cant be in comlex zeta fucntion will be 0 and then 1/2 as rela numbers A more general statement known as the generalized Riemann hypothesis conjectures that neither the Riemann zeta function nor any Dirichlet L-series has a zero with real part larger than 1/2.