PRIME TWIN CONJUCTURE SOLUTION

my soulstion it solved already like infity /firts priem numebr = ifnity infity /secodn prime = ifnity infnity*infity /priem numebr first * preim numebr second = infintity infinty+firts numebr +secodn priem numebr = ifnfity so thus priem numebr coudk prduce ifnity infnity/3 = ifnityt ifnity /5 = ifnity ifnityt + ifnfiity = 3+5 = infintiy/8 = infinity consider two twin prime how P = e pow infinity if lim epowinfinity->infinityf(1+x+xsquare...) where 1 have coefficint of manys ) if P= e power infinty(prime infity) 2p+1 = 2e power infinity + 1 lim 2epowinfinity->infinityf(1+x+xsquare+xcube...) where 1 have coefficint of manys ) solution fo mine now if there si time intevale in these coefficients and values P= e power infinty(prime infity 2p+1 = 2e power infinity + 1 if infinity have time intervals and ifinity goes with time intervals 2p+1.p =epow infinty( epow infinty +1) =e pow 2infinnity +1 now if we do in rhs side -4 -3 so two lcosuse or twins come 2p+1.p = e pow 2 infifntiy/2 + epow infity/4 then alos so we coudl get 2p+1/2.p/4 and it also a prime so two twins is coudl rpduce prime sother si infiate numebr of pairs of prime if we remove expoenetial tahtw e atkesn we also coudl achieve this so this means fi w ehav etime variable then one ifntity numebr coudl pruduce by two pprime numberses and then if the avlue si expsonetila then alll 2p there is infine numebr of pairs fo twin prime if w devide expoennet pow infinity by genrated by variable e pow infinity / e pow infinity -2 then e 2 will gate by prime number nature it self that cnjuction callled a bounded conjuction of infinity if twin primme number has infinity numbers then they exculate by prime divison number infinite prime and means an p becomes e pow infintit.T pow -T(infity time it dedeuct the value from epow infinity 2p+1 = 2e power infinity.T pow -T + 1 by that time varibale we bound the value till the time dialation not happens with them to achieves tw resualat avlue we cosndier in revaerse of tim avlue decued and to 1 and with time interval it deuce the value of secodn numebr to rpduce prime numebr priem nummebr given value of infity by rpiem numebers when with time T will be pwoer of psotive T and x = T(in shape of prime numebr) become then value will increase in priem numebr sitaution with time means when time pwoer its own time and expeoent where time is goes prime then lim T->infifnity p=epowT-x.Tpow-T+x)+1 but coffircnt fo x will increase conusosuly to prodce numebr where x->n x tends to n and T pow -T not multiply it conjuction with which time varaible will atke only to reoslave th complexity and denoted to how time increaseingly to create prime values contnously to achive twin prime thne 2p+1 =2epowT-x.Tpow-T+x)+1 extar coffieicnt to increases time limit is where T is tends to infinity here si that states that infinite number called time ahs two twin primen so in some way som how they will give n to prodcue infity if we fdrop becasue time variest left sides that stops the rotaion fo numbers T coudl comens such thsoe dialtion smaee time to prduce numebrs if we take eprido fo time then also we could achive multipel prime like infity /firts priem numebr = ifnity infity /secodn prime = ifnity infnity*infity /priem numebr first * preim numebr second = infintity infinty+firts numebr +secodn priem numebr = ifnfity so thus priem numebr coudk prduce ifnity infnity/3 = ifnityt ifnity /5 = ifnity ifnityt + ifnfiity = 3+5 = infintiy/8 = infinity